Conclusion
-1.
divides(nn!1,
i!1)
-2.
divides(nn!1,
j!1)
-3.
FORALL
mm
:
(divides(mm,
i!1)
AND
divides(mm,
j!1))
IMPLIES
(mm
<
=
nn!1)
-4.
(i!1
/=
0)
OR
(j!1
/=
0)
1.
FORALL
x
:
(divides(x,
i!1)
AND
divides(x,
j!1))
IMPLIES
(x
<
=
nn!1)