Conclusion
-1.
max({k:posnat
|
divides(k,
i!1)
AND
divides(k,
j!1)})
>
0
-2.
divides(max({k:posnat
|
divides(k,
i!1)
AND
divides(k,
j!1)}),
i!1)
-3.
divides(max({k:posnat
|
divides(k,
i!1)
AND
divides(k,
j!1)}),
j!1)
-4.
FORALL
x
:
(divides(x,
i!1)
AND
divides(x,
j!1))
IMPLIES
(x
<
=
max({k:posnat
|
divides(k,
i!1)
AND
divides(k,
j!1)}))
-5.
(i!1
/=
0)
OR
(j!1
/=
0)
1.
divides(max({k:posnat
|
divides(k,
i!1)
AND
divides(k,
j!1)}),
i!1)
AND
divides(max({k:posnat
|
divides(k,
i!1)
AND
divides(k,
j!1)}),
j!1)