Conclusion
-1.
FORALL
x:T
:
member(x,
V!1)
=
>
member(x,
vert(G!1))
1.
(vert(G!1)(x!1)
AND
V!1(x!1))
=
V!1(x!1)
Tactic
INST?
Premise 1.   (has proof of 3 steps)
-1.
member(x!1,
V!1)
=
>
member(x!1,
vert(G!1))
1.
(vert(G!1)(x!1)
AND
V!1(x!1))
=
V!1(x!1)