Conclusion
-1.
FORALL
e:doubleton[T]
:
edges(G!1)(e)
IMPLIES
(FORALL
x:T
:
e(x)
IMPLIES
vert(G!1)(x))
-2.
edges(G!1)(e!1)
AND
(FORALL
x:T
:
e!1(x)
IMPLIES
V!1(x))
-3.
e!1(x!1)
1.
vert(G!1)(x!1)
AND
V!1(x!1)
Tactic
INST?
Premise 1.   (has proof of 5 steps)
-1.
edges(G!1)(e!1)
IMPLIES
(FORALL
x:T
:
e!1(x)
IMPLIES
vert(G!1)(x))
-2.
edges(G!1)(e!1)
AND
(FORALL
x:T
:
e!1(x)
IMPLIES
V!1(x))
-3.
e!1(x!1)
1.
vert(G!1)(x!1)
AND
V!1(x!1)