Conclusion
-1.
subset?({e:doubleton[T]
|
edges(G!1)(e)
AND
(FORALL
x:T
:
e(x)
IMPLIES
V!1(x))},
edges(G!1))
IMPLIES
is
finite({e:doubleton[T]
|
edges(G!1)(e)
AND
(FORALL
x:T
:
e(x)
IMPLIES
V!1(x))})
1.
is
finite[doubleton[T]]({e:doubleton[T]
|
edges(G!1)(e)
AND
(FORALL
x:T
:
e(x)
IMPLIES
V!1(x))})