Nuprl Rule : axiomSqequalN

This rule proved as lemma rule_cequiv_member_eq_true3 in file rules/rules_squiggle6.v
at https://github.com/vrahli/NuprlInCoq

H  ⊢ Ax = Ax ∈ (a ~n b)

  BY axiomSqequalN ()

  H  ⊢ a ~n b

Definitions occuring in rule : equal: s = t ∈ T, sqequal_n: s ~n t, axiom: Ax

Latex:
H \mvdash{} Ax = Ax BY axiomSqequalN () H \mvdash{} a \msim{}n b Date html generated: 2019_06_20-PM-04_12_07 Last ObjectModification: 2018_09_17-AM-08_02_20 Theory : rules Home Index